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8b^2-4b-180=0
a = 8; b = -4; c = -180;
Δ = b2-4ac
Δ = -42-4·8·(-180)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-76}{2*8}=\frac{-72}{16} =-4+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+76}{2*8}=\frac{80}{16} =5 $
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